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The electric field associated with an e.m. wave in vacuum is given by E = i 40 cos (kz – 6 x 10⁸ t), where E, z and t are in volt/m, meter and seconds respectively. The value of wave vector k is:
Options
(a) 2 m⁻¹
(b) 0.5 m⁻¹
(c) 6 m⁻¹
(d) 3 m⁻¹
Correct Answer:
2 m⁻¹
Explanation:
On comparing the given equation to
E = a₀i cos (ωt – kz) ω = 6 x 10⁸ ,
k = 2π / r = ω / c
k = ω / c = 6 x 10⁸ / 3 x 10⁸ = 2 m⁻¹
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Topics: Electromagnetic Waves
(28)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Three blocks A,B and C of masses 4 kg, 2 kg and 1 kg respectively are in contact
- If 10000 V is applied across an X-ray tube, what will be the ratio of de-Broglie
- The time period of a simple pendulum in a lift descending with constant acceleration g is
- If by mistake voltmeter is connected in series and ammeter in parallel then
- The length of second pendulum is 1 m on earth. If mass and diameter
Topics: Electromagnetic Waves (28)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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