| ⇦ | 
| ⇨ |
The electric field associated with an e.m. wave in vacuum is given by E = i 40 cos (kz – 6 x 10⁸ t), where E, z and t are in volt/m, meter and seconds respectively. The value of wave vector k is:
Options
(a) 2 m⁻¹
(b) 0.5 m⁻¹
(c) 6 m⁻¹
(d) 3 m⁻¹
Correct Answer:
2 m⁻¹
Explanation:
On comparing the given equation to
E = a₀i cos (ωt – kz) ω = 6 x 10⁸ ,
k = 2π / r = ω / c
k = ω / c = 6 x 10⁸ / 3 x 10⁸ = 2 m⁻¹
Related Questions: - If a solid sphere of mass 1 kg and radius 0.1 m rolls without slipping at a uniform
- A polarised light of intensity I₀ is passed through another polariser whose pass axis
- A particle of masses m is thrown upwards from the surface of the earth, with a velocity u
- The kinetic energy of an electron in the first excited state is
- Curie temperature above which
Topics: Electromagnetic Waves
(28)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If a solid sphere of mass 1 kg and radius 0.1 m rolls without slipping at a uniform
- A polarised light of intensity I₀ is passed through another polariser whose pass axis
- A particle of masses m is thrown upwards from the surface of the earth, with a velocity u
- The kinetic energy of an electron in the first excited state is
- Curie temperature above which
Topics: Electromagnetic Waves (28)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply