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The electric field associated with an e.m. wave in vacuum is given by E = i 40 cos (kz – 6 x 10⁸ t), where E, z and t are in volt/m, meter and seconds respectively. The value of wave vector k is:
Options
(a) 2 m⁻¹
(b) 0.5 m⁻¹
(c) 6 m⁻¹
(d) 3 m⁻¹
Correct Answer:
2 m⁻¹
Explanation:
On comparing the given equation to
E = a₀i cos (ωt – kz) ω = 6 x 10⁸ ,
k = 2π / r = ω / c
k = ω / c = 6 x 10⁸ / 3 x 10⁸ = 2 m⁻¹
Related Questions: - The interferance pattern is obtained with two coherent light sources of intensity
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Topics: Electromagnetic Waves
(28)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The interferance pattern is obtained with two coherent light sources of intensity
- A potentiometer wire of length 10 m and resistance 10 Ω per metre is connected in series
- Following figures show the arrangement of bar magnets in different configurations
- One mole of an ideal gas at an initial temperature of T K, does 6R joule of work
- Two sound waves of wavelengths 5m and 6m formed 30 beats in 3 seconds
Topics: Electromagnetic Waves (28)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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