| ⇦ | 
| ⇨ |
The drive shaft of an automobile rotates at 3600 rpm and transmits 80 HP up from the engine to the rear wheels.The torque developed by the engine is
Options
(a) 16.58 Nm
(b) 0.022 Nm
(c) 158.31 Nm
(d) 141.6 Nm
Correct Answer:
158.31 Nm
Explanation:
P = τω ⇒ τ = P/ω Given:- P = 80 HP = 80 x 746W = 59860 Nms⁻¹ ω = 3600 rpm = (3600/60) x 2π rad s⁻¹ = 120 π rad s⁻¹ τ = 59680/(120xπ) =158.31 Nm
Related Questions: - The moment of inertia of a uniform circular disc of radius R and mass M about an axis
- Two bodies of masses m and 4 m are moving with equal K.E. The ratio of their linear
- A resistance of 20 ohm is connected to a source of an alternating potential V
- Light with an energy flux of 25×10⁴ Wm⁻² falls on a perfectly reflecting surface
- The energy released in the fission of 1 kg of ₉₂U²³⁵ is (energy per fission = 200 MeV)
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The moment of inertia of a uniform circular disc of radius R and mass M about an axis
- Two bodies of masses m and 4 m are moving with equal K.E. The ratio of their linear
- A resistance of 20 ohm is connected to a source of an alternating potential V
- Light with an energy flux of 25×10⁴ Wm⁻² falls on a perfectly reflecting surface
- The energy released in the fission of 1 kg of ₉₂U²³⁵ is (energy per fission = 200 MeV)
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply