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The drive shaft of an automobile rotates at 3600 rpm and transmits 80 HP up from the engine to the rear wheels.The torque developed by the engine is
Options
(a) 16.58 Nm
(b) 0.022 Nm
(c) 158.31 Nm
(d) 141.6 Nm
Correct Answer:
158.31 Nm
Explanation:
P = τω ⇒ τ = P/ω Given:- P = 80 HP = 80 x 746W = 59860 Nms⁻¹ ω = 3600 rpm = (3600/60) x 2π rad s⁻¹ = 120 π rad s⁻¹ τ = 59680/(120xπ) =158.31 Nm
Related Questions: - A body oscillates with amplitude of 10 cm in a horizontal platform.
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Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body oscillates with amplitude of 10 cm in a horizontal platform.
- Three blocks A,B and C of masses 4 kg, 2 kg and 1 kg respectively are in contact
- A person holding a rifle (mass of person and rifle together is 100 kg) stands on a smooth
- A parallel plate condenser has a uniform electric field E(V/m) in the space between
- An engine has an efficiency of 1/6. When the temperature of sink is reduced
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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