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The drive shaft of an automobile rotates at 3600 rpm and transmits 80 HP up from the engine to the rear wheels.The torque developed by the engine is
Options
(a) 16.58 Nm
(b) 0.022 Nm
(c) 158.31 Nm
(d) 141.6 Nm
Correct Answer:
158.31 Nm
Explanation:
P = τω ⇒ τ = P/ω Given:- P = 80 HP = 80 x 746W = 59860 Nms⁻¹ ω = 3600 rpm = (3600/60) x 2π rad s⁻¹ = 120 π rad s⁻¹ τ = 59680/(120xπ) =158.31 Nm
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Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The angular momentum of an electron is J. The magnitude of the magnetic moment
- According to Hook’s law, force is proportional to
- CO₂ laser uses
- The condition for obtaining secondary maxima in the diffraction pattern
- A current of 5 A is passing through a metallic wire of cross-sectional area 4×10⁻⁶ m².
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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