| ⇦ | 
| ⇨ |
The distance travelled by a particle starting from rest and moving with an acceleration 4/3 ms⁻², in the third second is
Options
(a) 10/3 m
(b) 19/3 m
(c) 6 m
(d) 4 m
Correct Answer:
10/3 m
Explanation:
Distance travelled in the nth second is given by tₙ = u + a/2 (2n – 1)
put u= 0, a= 4/3 ms⁻², n= 3 d= 0 + 4/ 3×2 (2 x 3 – 1) = 4/6 x 5 = 10/ 3 m
Related Questions: - The resistance of a bulb filament is 100 Ω at a temperature of 100⁰C.
- The magnetic field in a certain region of space is given by B =8.35×10⁻² Î T.
- A glass slab consists of thin uniform layers of progressively decreasing refractive
- RMS velocity of gas is proportional to
- A stone is dropped from a height h. It hits the ground with a certain momentum P. If the same stone is dropped from a height 100
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The resistance of a bulb filament is 100 Ω at a temperature of 100⁰C.
- The magnetic field in a certain region of space is given by B =8.35×10⁻² Î T.
- A glass slab consists of thin uniform layers of progressively decreasing refractive
- RMS velocity of gas is proportional to
- A stone is dropped from a height h. It hits the ground with a certain momentum P. If the same stone is dropped from a height 100
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply