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The distance travelled by a particle starting from rest and moving with an acceleration (4/3)ms⁻², in the 3rd second is
Options
(a) 6 m
(b) 4 m
(c) 10/3 m
(d) 19/3 m
Correct Answer:
10/3 m
Explanation:
Distance travelled in the nth second is given by tₙ = u + a/2 (2n – 1)
put u= 0, a= 4/3 ms⁻², n= 3
d= 0 + 4/ 3×2 (2 x 3 – 1) = 4/6 x 5 = 10/ 3 m
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary
- A stone of mass 1 kg tied to a light inexensible string of length L=10/3 is whirling
- A lift is moving down with acceleration a.A man in the lift drops a ball
- If the image formed by a convex mirror of focal length 30 cm is a quarter of the size
- A 36 Ω galvanometer is shunted by resistance of 4 Ω. The percentage of the total current
Question Type: Apply (15)
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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