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The distance travelled by a particle starting from rest and moving with an acceleration (4/3)ms⁻², in the 3rd second is
Options
(a) 6 m
(b) 4 m
(c) 10/3 m
(d) 19/3 m
Correct Answer:
10/3 m
Explanation:
Distance travelled in the nth second is given by tₙ = u + a/2 (2n – 1)
put u= 0, a= 4/3 ms⁻², n= 3
d= 0 + 4/ 3×2 (2 x 3 – 1) = 4/6 x 5 = 10/ 3 m
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If α (current gain) of transistor is 0.98, then what is the value of β
- The moon’s radius is 1/ 4 that of the earth and its mass is 1 / 80 times that of the earth
- A radioactive substance emits n beta particles in the first 2 s and 0.5 n beta
- A student performs an experiment to determine the Young’s modulus of a wire
- Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å
Question Type: Apply (15)
Difficulty Level: Easy (1008)
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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