| ⇦ | 
| ⇨ |
The displacement of a particle varies according to the relation x=4 (cos π t + sin π t). The amplitude of the particle is
Options
(a) 8
(b) -4
(c) 4
(d) 4 √2
Correct Answer:
4 √2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A particle A suffers on oblique elastic collision with a particle B that
- By the succesive disintegration of ₉₂U²³⁸, the final product obtained is ₈₂Pb²⁰⁶, then
- A body of mass 1 kg is thrown upwards with a velocity 20 m/s. It momentarily
- For a satellite escape velocity is 11 kms⁻¹.If the satellite is launched at an angle
- An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle A suffers on oblique elastic collision with a particle B that
- By the succesive disintegration of ₉₂U²³⁸, the final product obtained is ₈₂Pb²⁰⁶, then
- A body of mass 1 kg is thrown upwards with a velocity 20 m/s. It momentarily
- For a satellite escape velocity is 11 kms⁻¹.If the satellite is launched at an angle
- An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply