| ⇦ |
| ⇨ |
The dimensions of universal gas constant are
Options
(a) [ML²T⁻²θ⁻¹]
(b) [M²LT⁻²θ]
(c) [ML³T⁻²θ⁻¹]
(d) None of these
Correct Answer:
[ML²T⁻²θ⁻¹]
Explanation:
According to Ideal gas equation, PV = nRT
where P is the pressure, V is the volume, n is the no of moles, R is gas constant and T is temperature.
now , R = PV/nT
dimension of pressure = [ML⁻¹T⁻²]
dimension of volume = [ L³ ]
dimension of mole = no dimension
dimension of temperature = [ θ]
So , dimension of R =[ML⁻¹T⁻²][L³]/[θ]
=[ ML²T⁻²θ⁻¹]
Related Questions: - A spherical drop of mercury having a potential of 2.5 v is obtained as a result
- Two point charge +9e and +e are at 16 cm away from each other.
- A coil of resistance 20 ohm and inductance 5H is connected with a 100V battery
- If force(F), Velocity(V) and time(T) are taken as fundamental units, then the dimensions
- A light emitting diode(LED) has a voltage drop of 2 volt across it
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Physical World and Measurement
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A spherical drop of mercury having a potential of 2.5 v is obtained as a result
- Two point charge +9e and +e are at 16 cm away from each other.
- A coil of resistance 20 ohm and inductance 5H is connected with a 100V battery
- If force(F), Velocity(V) and time(T) are taken as fundamental units, then the dimensions
- A light emitting diode(LED) has a voltage drop of 2 volt across it
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Physical World and Measurement (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply