| ⇦ | 
| ⇨ |
The dimensional formula of Plancks’s constant and angular momentum are
Options
(a) ML²T⁻¹ and MLT⁻¹
(b) ML²T⁻¹ and ML²T⁻¹
(c) MT⁻¹ and MLT⁻¹
(d) ML²T⁻² and ML²T⁻¹
Correct Answer:
ML²T⁻¹ and ML²T⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A body of mass M hits normally a rigid wall with velocity V and bounces back
- The mass of a ⁷₃ Li nucleus is 0.042 u less than the sum of the masses of all its nucleons
- If an electron and a positron annihilate, the energy released is
- A resistance of 20 ohm is connected to a source of an alternating potential V
- A straight conductor of length 0.4 m is moved with a speed of 7 ms⁻¹perpendicular
Topics: Physical World and Measurement
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body of mass M hits normally a rigid wall with velocity V and bounces back
- The mass of a ⁷₃ Li nucleus is 0.042 u less than the sum of the masses of all its nucleons
- If an electron and a positron annihilate, the energy released is
- A resistance of 20 ohm is connected to a source of an alternating potential V
- A straight conductor of length 0.4 m is moved with a speed of 7 ms⁻¹perpendicular
Topics: Physical World and Measurement (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply