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The dimension of 1/2ε₀E², where ε₀ is permittivity of free space and E is electric field, is:
Options
(a) ML²T⁻²
(b) ML⁻¹T⁻²
(c) ML²T⁻¹
(d) MLT⁻¹
Correct Answer:
ML⁻¹T⁻²
Explanation:
1/2 ?¬ツタE² represents energy density i.e., energy per unit volume.
⇒ [ 1/2 ?¬ツタE² ] = ML²T⁻² / L³
= ML⁻¹T⁻²
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Question Type: Memory
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body of mass 3 kg is under a constant force which cause a displacement
- A total charge of 5µC is distributed uniformly on the surface of the thin walled
- Thin uniform rod of length L, cross-sectional area A and density ρ is rotated
- The numebr 0 (zero) is required for
- A gaussian sphere encloses an electric dipole within it. The total flux
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Physical World and Measurement (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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