The dimension of 1/2ε₀E², where ε₀ is permittivity of free space and E is electric field

⇦

⇨

The dimension of 1/2ε₀E², where ε₀ is permittivity of free space and E is electric field, is:

Options

(a) ML²T⁻²
(b) ML⁻¹T⁻²
(c) ML²T⁻¹
(d) MLT⁻¹

Correct Answer:

ML⁻¹T⁻²

Explanation:

1/2 ?￢ﾂﾀE² represents energy density i.e., energy per unit volume.
⇒ [ 1/2 ?￢ﾂﾀE² ] = ML²T⁻² / L³
= ML⁻¹T⁻²

Related Questions:

1. When there is no heat change from surroundings in a system, then the process
2. Two spherical bodies of mass M and 5 M and radii R and 2 R released in free space
3. A particle of mass 100g tied to a string is rotated along a circle of radius 0.5 m
4. On bombarding U²³⁵ by slow neutron, 200 MeV energy is released. If the power output
5. Two parallel beams of positron moving in the same direction will

Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Physical World and Measurement (103)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends