| ⇦ | 
| ⇨ |
The dimension of 1/2ε₀E², where ε₀ is permittivity of free space and E is electric field, is:
Options
(a) ML²T⁻²
(b) ML⁻¹T⁻²
(c) ML²T⁻¹
(d) MLT⁻¹
Correct Answer:
ML⁻¹T⁻²
Explanation:
1/2 ?￢ﾂﾀE² represents energy density i.e., energy per unit volume.
⇒ [ 1/2 ?￢ﾂﾀE² ] = ML²T⁻² / L³
= ML⁻¹T⁻²
Related Questions: - A thin prism of angle 15⁰ made of glass of refractive index µ₁ = 1.5 is combined
- Force required to move a mass of 1kg at rest on a horizontal rough plane
- Two cells when connected in series are balanced on 8m on a potentiometer.
- Shearing stress causes change in
- In a P-N junction
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Physical World and Measurement
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A thin prism of angle 15⁰ made of glass of refractive index µ₁ = 1.5 is combined
- Force required to move a mass of 1kg at rest on a horizontal rough plane
- Two cells when connected in series are balanced on 8m on a potentiometer.
- Shearing stress causes change in
- In a P-N junction
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Physical World and Measurement (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply