The dimension of 1/2ε₀E², where ε₀ is permittivity of free space and E is electric field

⇦

⇨

The dimension of 1/2ε₀E², where ε₀ is permittivity of free space and E is electric field, is:

Options

(a) ML²T⁻²
(b) ML⁻¹T⁻²
(c) ML²T⁻¹
(d) MLT⁻¹

Correct Answer:

ML⁻¹T⁻²

Explanation:

1/2 ?￢ﾂﾀE² represents energy density i.e., energy per unit volume.
⇒ [ 1/2 ?￢ﾂﾀE² ] = ML²T⁻² / L³
= ML⁻¹T⁻²

Related Questions:

1. A Carnot engine takes heat from a reservoir at 627⁰C and rejects heat
2. In the diffraction pattern of a single slit
3. A force of 5 N is acting on an object. Displacement of object is 10 m and the work done
4. When a ceiling fan is switched off its angular velocity reduces to 50% while
5. A particle having a mass of 10⁻² kg carries a charge of 5 x 10⁻⁸C

Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Physical World and Measurement (103)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends