| ⇦ | 
| ⇨ |
The diazotization of two feebly basic aromatic amines is achieved by using
Options
(a) nitrous acid
(b) nitrosyl-hydrochloric acid
(c) sulphuric acid
(d) nitrosoyl-sulphuric acid
Correct Answer:
nitrous acid
Explanation:
Diazotisation reaction of aromatic amine takes place in presence of nitrous acid obtained from NaNO₂ and HCl.
NaNO₂ + HCl → HNO₂ + NaCl.
Related Questions: - If 30 mL of H₂ and 20 mL of O₂ reacts to form water. what is left at the end
- Chlorine acts as bleaching agent only in the presence of
- For the cell reactionCu²⁺ (C₁.aq) + Zn(s) = Zn²⁺(C₂.aq ) + Cu(s)
- When 0.1 mol MnO₄²⁻ is oxidised the quantity of electricity required to completely
- Reaction BaO₂(s) ⇌ BaO(s) + O₂(g) ; ΔH = +ve.In equilibrium condition,
Topics: Organic compounds containing Nitrogen
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If 30 mL of H₂ and 20 mL of O₂ reacts to form water. what is left at the end
- Chlorine acts as bleaching agent only in the presence of
- For the cell reactionCu²⁺ (C₁.aq) + Zn(s) = Zn²⁺(C₂.aq ) + Cu(s)
- When 0.1 mol MnO₄²⁻ is oxidised the quantity of electricity required to completely
- Reaction BaO₂(s) ⇌ BaO(s) + O₂(g) ; ΔH = +ve.In equilibrium condition,
Topics: Organic compounds containing Nitrogen (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply