| ⇦ |
| ⇨ |
The depth at which the effective value of acceleration due to gravity is g/4 is (R=Radius of earth)
Options
(a) R
(b) 3R/4
(c) R/2
(d) R/4
Correct Answer:
3R/4
Explanation:
The effect of depth of acceleration due to gravity is g’=g(1-d/R)
Given, g’=g/4
g/4=g(1-d/R)
(g/4)/g=(1-d/R)
1/4=1-d/R ⇒d/R=1-1/4 ⇒3/4
d=3R/4
Related Questions: - For inelastic collision between two spherical rigid bodies
- A potentiometer circuit has been set up for finding the internal resistance of a given
- Two identical flutes produce fundamental notes of frequency 300 Hz at 27° C
- A particle has initial velocity (2i⃗+3j⃗) and acceleration (0.3i⃗+0.2j⃗). The magnitude
- A particle covers half of its total distance with speed v1 and the rest half distance
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For inelastic collision between two spherical rigid bodies
- A potentiometer circuit has been set up for finding the internal resistance of a given
- Two identical flutes produce fundamental notes of frequency 300 Hz at 27° C
- A particle has initial velocity (2i⃗+3j⃗) and acceleration (0.3i⃗+0.2j⃗). The magnitude
- A particle covers half of its total distance with speed v1 and the rest half distance
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply