| ⇦ |
| ⇨ |
The correct set of four quantum numbers for the valence electron of rubidium atom(Z=37) is
Options
(a) 5,1,1,+½
(b) 6,0,0,+½
(c) 5,0,0,+½
(d) 5,1,0,+½
Correct Answer:
5,0,0,+½
Explanation:
₃₇Rb=₃₆[Kr] 5s
Its valence electron in 5s¹.
so, n= 5
/= 0 (For s oribital)
m= 0 (As m= -/ to 0 to +/)
s= +½.
Related Questions: - Libermann’s nitroso reaction may be used as a test for
- Acetylene, on reacting with formaldehyde under high pressure, gives
- If 0.44g of a colourless oxide of nitrogen occupies 224 ml at 1520 mm of Hg and 273⁰C
- Absolute temperature is the temperature at which
- Correct order of the stability of group IIA metal carbonates is
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Libermann’s nitroso reaction may be used as a test for
- Acetylene, on reacting with formaldehyde under high pressure, gives
- If 0.44g of a colourless oxide of nitrogen occupies 224 ml at 1520 mm of Hg and 273⁰C
- Absolute temperature is the temperature at which
- Correct order of the stability of group IIA metal carbonates is
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply