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The correct set of four quantum numbers for the valence electron of rubidium atom(Z=37) is
Options
(a) 5,1,1,+½
(b) 6,0,0,+½
(c) 5,0,0,+½
(d) 5,1,0,+½
Correct Answer:
5,0,0,+½
Explanation:
₃₇Rb=₃₆[Kr] 5s
Its valence electron in 5s¹.
so, n= 5
/= 0 (For s oribital)
m= 0 (As m= -/ to 0 to +/)
s= +½.
Related Questions: - The equivalent weight of H₃PO₂, when it disproportionates into PH₃ and H₃PO₃ is
- Which one of the following is true in electrolytic refining
- Which of the following does not have a metal-carbon bond
- Which of the following elements will have the lowest first ionisation energy?
- The unit of rate constant depends upon
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The equivalent weight of H₃PO₂, when it disproportionates into PH₃ and H₃PO₃ is
- Which one of the following is true in electrolytic refining
- Which of the following does not have a metal-carbon bond
- Which of the following elements will have the lowest first ionisation energy?
- The unit of rate constant depends upon
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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