⇦ | ⇨ |
The correct set of four quantum numbers for the valence electron of rubidium atom(Z=37) is
Options
(a) 5,1,1,+½
(b) 6,0,0,+½
(c) 5,0,0,+½
(d) 5,1,0,+½
Correct Answer:
5,0,0,+½
Explanation:
₃₇Rb=₃₆[Kr] 5s
Its valence electron in 5s¹.
so, n= 5
/= 0 (For s oribital)
m= 0 (As m= -/ to 0 to +/)
s= +½.
Related Questions: - Which of the following yield both alkane and alkene
- Which of the following inert gases does not have eight electrons
- Which of the following gases are poisonous
- 1.0g of magnesium is burnt with 0.56 g O₂ in a closed vessel
- The total number of atomic orbitals in fourth energy level of an atom is :
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following yield both alkane and alkene
- Which of the following inert gases does not have eight electrons
- Which of the following gases are poisonous
- 1.0g of magnesium is burnt with 0.56 g O₂ in a closed vessel
- The total number of atomic orbitals in fourth energy level of an atom is :
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply