| ⇦ | 
| ⇨ |
If ionization potential for hydrogen atom is 13.6eV, then ionization potential for He⁺ will be
Options
(a) 54.4 eV
(b) 6.8 eV
(c) 13.6 eV
(d) 24.5 eV
Correct Answer:
54.4 eV
Explanation:
The ionization energy of any hydrogen like species (having one electron only) is given by the equation I.E = (2π²Z²me⁴)/h². Since the atomic number of H is 1 and that of He is 2, therefore,the I.E. of He⁺ is four times = Z²=(2²) the I.E. of H. So, 13.6 x 4= 54.4 eV
Related Questions: - The general molecular formula for a cycloalkyl group is
- The complex [CoF₆]⁴⁻ is
- If 1 litre of N₂ is mixed with 2 litre of O₂, quantity explaining it is
- Which one of the following methods is used to prepare Me₃COEt with a good yield
- Which of the following gives propyne on hydrolysis
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The general molecular formula for a cycloalkyl group is
- The complex [CoF₆]⁴⁻ is
- If 1 litre of N₂ is mixed with 2 litre of O₂, quantity explaining it is
- Which one of the following methods is used to prepare Me₃COEt with a good yield
- Which of the following gives propyne on hydrolysis
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply