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The compound that gives both iodoform and Fehling’s tests is
Options
(a) ethanol
(b) propanone
(c) 2-butanol
(d) ethanal
Correct Answer:
ethanal
Explanation:
CH₃CHO gives test for aldehyde (Fehling’s test) and iodoform test. CH₃CHO + 2Cu²⁺ + 3OH⁻(Fehling’s solution) → CH₃COO⁻ + 2Cu⁺(Red ppt.) + 2H₂O. CH₃CHO + NaOH + I₂ → HCOONa + CHI₃(Iodoform).
Related Questions: - By which of the following processes permanent hardness of water can be removed
- Which one of the following is an appropriate method of separating benzene
- The neutralisation of a strong acid by a strong base liberates an amount
- The cylindrical shape of an alkyne is due to
- Replacement of Cl of chlorobenzene to give phenol requires drastic conditions.
Topics: Aldehydes Ketones and Carboxylic Acid
(89)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- By which of the following processes permanent hardness of water can be removed
- Which one of the following is an appropriate method of separating benzene
- The neutralisation of a strong acid by a strong base liberates an amount
- The cylindrical shape of an alkyne is due to
- Replacement of Cl of chlorobenzene to give phenol requires drastic conditions.
Topics: Aldehydes Ketones and Carboxylic Acid (89)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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