| ⇦ | 
| ⇨ |
The complex [CoF₆]⁴⁻ is
Options
(a) outer orbital and diamagnetic
(b) inner orbital and paramagnetic
(c) outer orbital and paramagnetic
(d) inner orbital and diamagnetic
Correct Answer:
outer orbital and paramagnetic
Explanation:
Co²⁺ (d⁷) forms an outer orbital and paramagnetic complex due to presence of 3 unpaired electrons.
Related Questions: - Solubility of MX₂ – type electrolytes is 0.5 ˣ 10⁻⁴ mol/L.,
- Aqueous solution of Cu (II) gives an intense blue solution with ammonia,which is due
- Benzenamine reacts with excess bromine to produce
- An important product in the ozone depletion by chlorofluorocarbons is
- What is the product of the reaction of phenol with CHCl₃ in aqueous NaOH
Topics: Coordination Compounds
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Solubility of MX₂ – type electrolytes is 0.5 ˣ 10⁻⁴ mol/L.,
- Aqueous solution of Cu (II) gives an intense blue solution with ammonia,which is due
- Benzenamine reacts with excess bromine to produce
- An important product in the ozone depletion by chlorofluorocarbons is
- What is the product of the reaction of phenol with CHCl₃ in aqueous NaOH
Topics: Coordination Compounds (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply