| ⇦ | 
| ⇨ |
Fine the magnetic moment of a divalent ion in aqueous solution if its atomic number is 25
Options
(a) 3.9 B.M.
(b) 4.49 B.M.
(c) 5.9 B.M.
(d) 6.9 B.M.
Correct Answer:
5.9 B.M.
Explanation:
Magnetic Moment (µ) = √n(n+2). Where n = number of unpaired electrons. Atomic Number 25 = 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁵ 4s². n = 5. Therefore it is divalent so 4s⁰ in M²⁺ and n = 5. Therefore µ = √5(5+2) = √5 *7 = √35. = 5.916 BM = 5.9 B.M.
Related Questions: - Volume of 0.1 M K₂Cr₂O₇ required to oxidize 35 mL of 0.5 M FeSO₄ solution is
- What is the packet of energy called?
- The equation ΔG = ΔH – TΔS is for
- Which of the following practices will not come under green chemistry
- In the electrolysis of aqueous solution of CuSO₄ using copper electrodes, the
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Volume of 0.1 M K₂Cr₂O₇ required to oxidize 35 mL of 0.5 M FeSO₄ solution is
- What is the packet of energy called?
- The equation ΔG = ΔH – TΔS is for
- Which of the following practices will not come under green chemistry
- In the electrolysis of aqueous solution of CuSO₄ using copper electrodes, the
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply