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The change in oxidation state of sulphur when sulphur dioxide is passed in an acidified K₂Cr₂O₇ solution is from
Options
(a) 4 to 0
(b) 4 to 2
(c) 4 to 6
(d) 6 to 4
Correct Answer:
4 to 6
Explanation:
Acidified K₂Cr₂O₇ solution oxidised SO₂ into Cr₂(SO₄)₃.
3SO₂ + K₂Cr₂O₇ + H₂O → K₂SO₄ + Cr₂(SO₄)₃ + H₂O
Oxidation of S =+4
Oxidation of (SO₄) = +6
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Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The charge on the central metal ion in the complex[Ni(CO)₄] is
- In the brown ring test for the nitrate ion, the brown colour is due to
- The ore horn silver corresponds to
- At 0K, (i) ¹²C and (ii) a mixture of ¹²C and ¹⁴C will
- H₂S₂O₇ has a commercial name as
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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