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In the brown ring test for the nitrate ion, the brown colour is due to
Options
(a) [Fe(H₂O)₅NO]²⁺
(b) [Fe(H₂O)₅NO]³⁺
(c) [Fe(H₂O)₆]⁺
(d) [Fe(H₂O)₅NO₂]²⁺
Correct Answer:
[Fe(H₂O)₅NO]²⁺
Explanation:
When an aqueous solution of the nitrate salt is treated with freashly prepared solution of ferrous sulphate and concentrated H₂SO₄, a brown ring is formed on account of the formation of complex [Fe(H₂O)₅NO]SO₄ at the junction of two liquids. NaNO₃ + H₂SO₄ → NaHSO₄ + HNO₃. 6FeSO₄ + 2HNO₃ + 3H₂SO₄ → 3Fe₂(SO₄)₃ + 4H₂O + 2NO. [Fe(H₂O)₆]SO₄.H₂O + NO → [Fe(H₂O)₅NO]SO₄ + 2H₂O(brown ring).
Related Questions: - Which compound is zero valent metal complex
- Gold number gives
- The standard emf for the cell reaction, 2Cu⁺(aq) → Cu(s) + Cu²⁺(aq)
- Surface tension vanishes at
- CuSO₄ dissolves in NH₃ due to the formation of
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which compound is zero valent metal complex
- Gold number gives
- The standard emf for the cell reaction, 2Cu⁺(aq) → Cu(s) + Cu²⁺(aq)
- Surface tension vanishes at
- CuSO₄ dissolves in NH₃ due to the formation of
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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