| ⇦ |
| ⇨ |
The change in oxidation state of sulphur when sulphur dioxide is passed in an acidified K₂Cr₂O₇ solution is from
Options
(a) 4 to 0
(b) 4 to 2
(c) 4 to 6
(d) 6 to 4
Correct Answer:
4 to 6
Explanation:
Acidified K₂Cr₂O₇ solution oxidised SO₂ into Cr₂(SO₄)₃.
3SO₂ + K₂Cr₂O₇ + H₂O → K₂SO₄ + Cr₂(SO₄)₃ + H₂O
Oxidation of S =+4
Oxidation of (SO₄) = +6
Related Questions: - XeF₆ on complete hydrolysis gives
- Bithional is generally added to the soaps as an additive to function as a
- Identify the correct order of the size of the following elements:
- The effective atomic number for [Rh(H₂O)₆]³⁺ (atomic number for Rh is 45) is
- 75% of a first order reaction was completed in 32min.When was 50% of the reaction
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- XeF₆ on complete hydrolysis gives
- Bithional is generally added to the soaps as an additive to function as a
- Identify the correct order of the size of the following elements:
- The effective atomic number for [Rh(H₂O)₆]³⁺ (atomic number for Rh is 45) is
- 75% of a first order reaction was completed in 32min.When was 50% of the reaction
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply