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The case of adsorption of the hydrated alkali metal ions on an ion-exchange resins follows the order:
Options
(a) Li⁺ < K⁺ < Na⁺ < Rb⁺
(b) Rb⁺ < K⁺ < Na⁺ < Li⁺
(c) K⁺ < Na⁺ < Rb⁺ < Li⁺
(d) Na⁺ < Li⁺ < K⁺ < Rb⁺
Correct Answer:
Rb⁺ < K⁺ < Na⁺ < Li⁺
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In which of the following reaction, the hydrogen peroxide is a reducing agent?
- What is the [OH⁻] in the final solution prepared by mixing 20 mL of 0.05 M Hcl
- The aqueous solution of which of the following salt will have the lowest pH
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- What is the approximate percentage of H₂O₂ in a sample labelled as 10 V?
Topics: S and Some P Block Elements
(157)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In which of the following reaction, the hydrogen peroxide is a reducing agent?
- What is the [OH⁻] in the final solution prepared by mixing 20 mL of 0.05 M Hcl
- The aqueous solution of which of the following salt will have the lowest pH
- The most common lanthanide is
- What is the approximate percentage of H₂O₂ in a sample labelled as 10 V?
Topics: S and Some P Block Elements (157)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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