| ⇦ | 
| ⇨ |
The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV, respectively. In the nuclear reaction ₃⁷Li+₁¹H→ ₂⁴He+ ₂⁴He+Q, the value of energy Q released is
Options
(a) 19.6 MeV
(b) (-24 MeV)
(c) 8.4 MeV
(d) 17.3 MeV
Correct Answer:
17.3 MeV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A body rolls down a stair case of 5 steps. Each step has height 0.1 m and width 0.1m
- Sodium has body centred packing. Distance between two nearest atoms is 3.7 Å.
- For the normal eye, the cornea of eye provides a converging power of 40D
- RMS velocity of gas is proportional to
- If the nucleus ²⁷₁₃Al has nuclear radius of about 3.6 fm
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body rolls down a stair case of 5 steps. Each step has height 0.1 m and width 0.1m
- Sodium has body centred packing. Distance between two nearest atoms is 3.7 Å.
- For the normal eye, the cornea of eye provides a converging power of 40D
- RMS velocity of gas is proportional to
- If the nucleus ²⁷₁₃Al has nuclear radius of about 3.6 fm
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply