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In Young’s double slit experiment, when wavelength used is 6000Å and the screen is 40 cm from the slits, the fringes are 0.012 cm wide. What is the distance between the slits?
Options
(a) 0.24 cm
(b) 0.2 cm
(c) 2.4 cm
(d) 0.024 cm
Correct Answer:
0.2 cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The energy released in the fission of 1 kg of ₉₂U²³⁵ is (energy per fission = 200 MeV)
- The wave described by y = 0.25 sin (10 2πx – 2πt), where x and y are in meters
- Two cells when connected in series are balanced on 8m on a potentiometer.
- In a water fall, the water falls from a height of 100 m. If the entire kinetic energy
- Consider 3rd orbit of He⁺(helium), using non-relativistic approach, the speed
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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