| ⇦ | 
| ⇨ |
The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV. If two deutrons are fused to form one ₂⁴He then the energy released is
Options
(a) 30.2 MeV
(b) 25.8 MeV
(c) 23.6 MeV
(d) 19.2 MeV
Correct Answer:
23.6 MeV
Explanation:
₁H² + ₁H² → ₂He⁴ + energy
.·. Energy released = B.E or ₂He⁴ – 2(B.E. of ₁H²)
= 28 – 2(2.2) = 28 – 4.4 = 23.6 Mev
Related Questions: - Infinite number of masses, each 1 kg, are placed along the x-axis
- The ratio of the dimensions of planck’s constant and that of the moment of inertia is
- Find the right condition(s) for Fraunhofer diffraction due to a single slit.
- Amout of heat required to raise the temperature of a body through 1 K is called its
- If X=3YZ², find dimensions of Y if X and Z are the dimensions of capacity
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Infinite number of masses, each 1 kg, are placed along the x-axis
- The ratio of the dimensions of planck’s constant and that of the moment of inertia is
- Find the right condition(s) for Fraunhofer diffraction due to a single slit.
- Amout of heat required to raise the temperature of a body through 1 K is called its
- If X=3YZ², find dimensions of Y if X and Z are the dimensions of capacity
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply