| ⇦ |
| ⇨ |
The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV. If two deutrons are fused to form one ₂⁴He then the energy released is
Options
(a) 30.2 MeV
(b) 25.8 MeV
(c) 23.6 MeV
(d) 19.2 MeV
Correct Answer:
23.6 MeV
Explanation:
₁H² + ₁H² → ₂He⁴ + energy
.·. Energy released = B.E or ₂He⁴ – 2(B.E. of ₁H²)
= 28 – 2(2.2) = 28 – 4.4 = 23.6 Mev
Related Questions: - A DC ammeter has resistance 0.1Ω and its current ranges 0-100A. If the range
- Two metal rods 1 and 2 of same lengths have same temperature difference
- Two metallic spheres of radii 1 cm and 3 cm are given charges of -1 x 10⁻² C
- Thin uniform rod of length L, cross-sectional area A and density ρ is rotated
- When the temperature increases, the viscocity of
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A DC ammeter has resistance 0.1Ω and its current ranges 0-100A. If the range
- Two metal rods 1 and 2 of same lengths have same temperature difference
- Two metallic spheres of radii 1 cm and 3 cm are given charges of -1 x 10⁻² C
- Thin uniform rod of length L, cross-sectional area A and density ρ is rotated
- When the temperature increases, the viscocity of
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply