The average power dissipated in a pure inductor is

The Average Power Dissipated In A Pure Inductor Is Physics Question

The average power dissipated in a pure inductor is

Options

(a) VI²/4
(b) 1/2 VI
(c) zero
(d) VI²

Correct Answer:

zero

Explanation:

In the inductor circuit, phase difference (ɸ) = 90° or π / 2

we know that, Pₐᵥ = V(rms) I(rms) cos ɸ = V(rms) I(rms) cos(π/2)

Therefore, Pₐᵥ = 0

Related Questions:

  1. Number of electrons in one mC charge, given e=1.6×10⁻¹⁹ C, will be
  2. A particle covers half of its total distance with speed v1 and the rest half distance
  3. An insulated container of gas has two champers seperated by an insulating partition.
  4. A boy standing at top of a tower of 20 m height drops a stone
  5. The electric potential at a point (x,y,z) is given by V = – x²y – xz³ + 4.

Topics: Alternating Current (96)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*