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| ⇨ |
The average power dissipated in a pure inductor is
Options
(a) VI²/4
(b) 1/2 VI
(c) zero
(d) VI²
Correct Answer:
zero
Explanation:
In the inductor circuit, phase difference (ɸ) = 90° or π / 2
we know that, Pₐᵥ = V(rms) I(rms) cos ɸ = V(rms) I(rms) cos(π/2)
Therefore, Pₐᵥ = 0
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Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two bodies of masses m₁ and m₂ and having velocities v₁ and v₂ respectively
- A particle falls towards earth from infinity. Its velocity on reaching the earth
- The total energy of a particle executing SHM is 80 J
- A force of 10 newton acts on a body of mass 20 kg for 10 seconds. Change in its momentum
- Following figures show the arrangement of bar magnets in different configurations
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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