| ⇦ | 
| ⇨ |
The area of cross-section of a steel wire (Y=2.0×10¹¹ N/m²) is 0.1 cm². The force required to double its length will be
Options
(a) 2×10¹² N
(b) 2×10¹¹ N
(c) 2×10¹⁰ N
(d) 2×10⁶ N
Correct Answer:
2×10⁶ N
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - An air core coil and an electric bulb are connected in series with an AC source.
- A student performs an experiment to determine the Young’s modulus of a wire
- A hemispherical bowl of radius R is rotating about its axis of symmetry
- If ₉₂U²³⁸ undergoes successively 8 ∝-decays and 6 β-decays, the resulting nucleus is
- The internal energy change in a system that has absorbed 2 kcals of heat
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An air core coil and an electric bulb are connected in series with an AC source.
- A student performs an experiment to determine the Young’s modulus of a wire
- A hemispherical bowl of radius R is rotating about its axis of symmetry
- If ₉₂U²³⁸ undergoes successively 8 ∝-decays and 6 β-decays, the resulting nucleus is
- The internal energy change in a system that has absorbed 2 kcals of heat
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply