| ⇦ |
| ⇨ |
The area of cross-section of a steel wire (Y=2.0×10¹¹ N/m²) is 0.1 cm². The force required to double its length will be
Options
(a) 2×10¹² N
(b) 2×10¹¹ N
(c) 2×10¹⁰ N
(d) 2×10⁶ N
Correct Answer:
2×10⁶ N
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The valence band and the conductance band of a solid overlap at low temperature
- A black body at 227⁰C radiates heat at the rate of 7cals/cm²s. At a temperature
- In depletion layer of unbiased P-N junction
- Two particles P and Q start from origin and execute simple harmonic motion along X-axis
- The dimensions of pressure are equal to those of
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The valence band and the conductance band of a solid overlap at low temperature
- A black body at 227⁰C radiates heat at the rate of 7cals/cm²s. At a temperature
- In depletion layer of unbiased P-N junction
- Two particles P and Q start from origin and execute simple harmonic motion along X-axis
- The dimensions of pressure are equal to those of
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply