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The area of cross-section of a steel wire (Y=2.0×10¹¹ N/m²) is 0.1 cm². The force required to double its length will be
Options
(a) 2×10¹² N
(b) 2×10¹¹ N
(c) 2×10¹⁰ N
(d) 2×10⁶ N
Correct Answer:
2×10⁶ N
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV
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Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV
- A wire of length 1 m is placed in a uniform magnetic field of 1.5 tesla at an angle
- For transistor action (1) Base, emitter and collector regions should have similar size
- A coil of resistance 20 ohm and inductance 5H is connected with a 100V battery
- A spring balance is attached to the ceiling of a lift.A man hangs his bag on the spring
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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