⇦ | ⇨ |
The area of cross-section of a steel wire (Y=2.0×10¹¹ N/m²) is 0.1 cm². The force required to double its length will be
Options
(a) 2×10¹² N
(b) 2×10¹¹ N
(c) 2×10¹⁰ N
(d) 2×10⁶ N
Correct Answer:
2×10⁶ N
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The temperature of ideal gas is reduced from 927° C to 27° C. The r.m.s velocity
- In circular coil, when number of turns is doubled and resistance becomes 1/4th
- If we study the vibration of a pipe open at both ends
- Calcium plate has a maximum possible radiation wavelength 400 nm to eject electrons.
- 180⁰ phase difference is obtained when light ray is reflected from
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The temperature of ideal gas is reduced from 927° C to 27° C. The r.m.s velocity
- In circular coil, when number of turns is doubled and resistance becomes 1/4th
- If we study the vibration of a pipe open at both ends
- Calcium plate has a maximum possible radiation wavelength 400 nm to eject electrons.
- 180⁰ phase difference is obtained when light ray is reflected from
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply