| ⇦ | 
| ⇨ |
The amount of electricity requried to deposit 0.9 g of aluminium, when the electrode reaction is Al³⁺ + 3e⁻ → Al
Options
(a) 9.65 ˣ 10⁴ C
(b) 1.93 ˣ 10⁴ C
(c) 9.65 ˣ 10³ C
(d) 4.34 ˣ 10⁵ C
Correct Answer:
9.65 ˣ 10³ C
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The two electrons in K-subshell will differ in
- The concentration of [H⁺] and [OH⁻] of a 0.1 M aqueous solution of 2% ionised
- The oxidation state of I in H₄IO₆⁻ is
- Which one of the following can differentitate between C₂H₅OH and CH₃OH
- The number of spherical nodes in 3p orbitals are
Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The two electrons in K-subshell will differ in
- The concentration of [H⁺] and [OH⁻] of a 0.1 M aqueous solution of 2% ionised
- The oxidation state of I in H₄IO₆⁻ is
- Which one of the following can differentitate between C₂H₅OH and CH₃OH
- The number of spherical nodes in 3p orbitals are
Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
For 27g of Al,
3 mole of electron=3F=289500c
For 0.9g of Al,
(289500/27)*0.9=9650