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The amount of electricity requried to deposit 0.9 g of aluminium, when the electrode reaction is Al³⁺ + 3e⁻ → Al
Options
(a) 9.65 ˣ 10⁴ C
(b) 1.93 ˣ 10⁴ C
(c) 9.65 ˣ 10³ C
(d) 4.34 ˣ 10⁵ C
Correct Answer:
9.65 ˣ 10³ C
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The adjacent sheets are bonded together in graphite with
- The neutralisation of a strong acid by a strong base liberates an amount
- KMnO₄ acts as an oxidising agent in the netural medium and gets reduced to MnO₂.
- The metal having the highest melting point is
- In an isobaric process, the ratio of heat supplied to the system (dQ)
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Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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For 27g of Al,
3 mole of electron=3F=289500c
For 0.9g of Al,
(289500/27)*0.9=9650