| ⇦ | 
| ⇨ |
The amount of copper deposited by one Faraday current will be maximum in an acidic solution of one litre of
Options
(a) 1 M Cu₂Cl₂
(b) 2 M Cu(NO₃)₂
(c) 5 M CuSO₄
(d) 5 M Cu₃(PO₄)₂
Correct Answer:
1 M Cu₂Cl₂
Explanation:
In 1 M Cu₂Cl₂. Cu⁺ (one faraday = 96500C) deposited = 63.5 g of Cu. In 2 M Cu(NO₃)₂. Cu²⁺ (2F = 2⨯96500C) deposited 63.5 of Cu. Therefore 1F deposited 63.5/2 g of Cu. In 5 M CuF₂. Cu²⁺ (2F = 2⨯96500 C) deposited 63.5 g of Cu. Therefore 1F = 96500 C deposited 63.5/2 g of Cu. so Cu deposited by 1 Faraday will be maximum in case of 1M Cu₂Cl₂.
Related Questions: - IF the bond energies of H – H , Br – Br and H – Br are 433 , 192 and 364 kJ mol⁻¹
- CO₂ is obtained by heating
- Choose the paramagnetic oxide in the following
- Oxidation number of carbon in CH₂Cl₂ is
- The temperature above which a gas cannot be liquefied is called as
Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- IF the bond energies of H – H , Br – Br and H – Br are 433 , 192 and 364 kJ mol⁻¹
- CO₂ is obtained by heating
- Choose the paramagnetic oxide in the following
- Oxidation number of carbon in CH₂Cl₂ is
- The temperature above which a gas cannot be liquefied is called as
Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply