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The alternating current in a circuit is given by I=50 sin314t. The peak value and frequency of the current are
Options
(a) I₀=25 A and f=100 Hz
(b) I₀=50 A and f=50 Hz
(c) I₀=50 A and f=100 Hz
(d) I₀=25 A and f=50 Hz
Correct Answer:
I₀=50 A and f=50 Hz
Explanation:
From standard equation, we have I = I₀ sin ωt —–(i)
Given, I = 50 sin 31 4t —-(ii)
Comparing equation (i) and (ii), we get I₀ = 50 A, ω = 2πf = 314
⇒ f = 314 / (2 × 3.14) = 50 Hz
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Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Graph of force per unit length between two long parallel current carrying
- The work function for metals A,B abd C are respectively 1.92 eV,2.0 eV and 5 eV.
- A mass m moves in a circle on a smooth horizontal plane with velocity v₀
- The potential energy of a weightless spring compressed by a distance D is proportional
- A straight conductor of length 0.4 m is moved with a speed of 7 ms⁻¹perpendicular
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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