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The alternating current in a circuit is given by I=50 sin314t. The peak value and frequency of the current are
Options
(a) I₀=25 A and f=100 Hz
(b) I₀=50 A and f=50 Hz
(c) I₀=50 A and f=100 Hz
(d) I₀=25 A and f=50 Hz
Correct Answer:
I₀=50 A and f=50 Hz
Explanation:
From standard equation, we have I = I₀ sin ωt —–(i)
Given, I = 50 sin 31 4t —-(ii)
Comparing equation (i) and (ii), we get I₀ = 50 A, ω = 2πf = 314
⇒ f = 314 / (2 × 3.14) = 50 Hz
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Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The periodic waves of intensities I₁ and I₂ pass through a region at the same time
- Two bodies of masses m₁ and m₂ and having velocities v₁ and v₂ respectively
- The velocity of radio-waves is 3×10⁵ km/s. The frequency corresponding to wavelength
- A beam of light of wavelength 600 nm from a distant source falls
- A particle in simple harmonic motion is described by the displacement function
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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