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The additional energy that should be given to an electron to reduce its de-Broglie wavelength from 1nm to 0.5nm is
Options
(a) 2 times the initial kinetic energy
(b) 3 times the initial kinetic energy
(c) 0.5 times the initial kinetic energy
(d) 4 times the initial kinetic energy
Correct Answer:
3 times the initial kinetic energy
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Excitation energy of a hydrogen like ion, in its first excitation state, is 40.8 eV.
- The velocity of radio-waves is 3×10⁵ km/s. The frequency corresponding to wavelength
- Which of the following transitions in hydrogen atoms emit photons of highest frequency?
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Excitation energy of a hydrogen like ion, in its first excitation state, is 40.8 eV.
- The velocity of radio-waves is 3×10⁵ km/s. The frequency corresponding to wavelength
- Which of the following transitions in hydrogen atoms emit photons of highest frequency?
- The drive shaft of an automobile rotates at 3600 rpm and transmits 80 HP
- A photocell employs photoelectric effect to convert
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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