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The additional energy that should be given to an electron to reduce its de-Broglie wavelength from 1nm to 0.5nm is
Options
(a) 2 times the initial kinetic energy
(b) 3 times the initial kinetic energy
(c) 0.5 times the initial kinetic energy
(d) 4 times the initial kinetic energy
Correct Answer:
3 times the initial kinetic energy
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - What is the Q-value of the reaction?
¹H+⁷Li→⁴He+⁴He
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What is the Q-value of the reaction? ¹H+⁷Li→⁴He+⁴He
- A 2 kg mass starts from rest on an inclined smooth surface with inclination
- Two spherical nuclei have mass numbers 216 and 64 with their radii R₁ and R₂,
- A wire of length 2 m is made from 10 cm³ of copper. A force F is applied so that
- The decay constant of a radio isotope is λ. If A₁ and A₂ are its activities at time
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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