| ⇦ | 
| ⇨ |
The acceleration of an electron in an electric field of magnitude 50 V/cm, if e/m value of the electron is 1.76×10¹¹ C/kg will be
Options
(a) 8.8×10¹⁴ m/sec²
(b) 3×10¹³ m/sec²
(c) 5.4×10¹² m/sec²
(d) Zero
Correct Answer:
8.8×10¹⁴ m/sec²
Explanation:
Acceleration = a = eE / m
⇒ a = 1.76 × 10¹¹ × 50 × 10 ¹²
⇒ a = 8.8 × 10 ¹⁴ m/ sec²
Related Questions: - A body of mass m is orbiting the earth at a radius r from the center of earth
- The fossil bone has a ¹⁴C:¹²C ratio, which is [1/16] of that in a living animal
- A long straight wire is carrying a current of 12 A. The magnetic field at a distance
- A boat of anchor is rocked by waves whose crests are 100 m apart and velocity
- The cadmium rods are used in nuclear reactor to
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body of mass m is orbiting the earth at a radius r from the center of earth
- The fossil bone has a ¹⁴C:¹²C ratio, which is [1/16] of that in a living animal
- A long straight wire is carrying a current of 12 A. The magnetic field at a distance
- A boat of anchor is rocked by waves whose crests are 100 m apart and velocity
- The cadmium rods are used in nuclear reactor to
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
E=50v/cm
=5000v/m
e/m=1.76×10power-11
F=ma
F=qĒ
ma=qĒ
a= e/m×Ē
=1.76×10 power11 × 5000
=8.8×10 power 14 m/sec sq.