The acceleration of an electron in an electric field of magnitude 50 V/cm,

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The acceleration of an electron in an electric field of magnitude 50 V/cm, if e/m value of the electron is 1.76×10¹¹ C/kg will be

Options

(a) 8.8×10¹⁴ m/sec²
(b) 3×10¹³ m/sec²
(c) 5.4×10¹² m/sec²
(d) Zero

Correct Answer:

8.8×10¹⁴ m/sec²

Explanation:

Acceleration = a = eE / m

⇒ a = 1.76 × 10¹¹ × 50 × 10 ¹²

⇒ a = 8.8 × 10 ¹⁴ m/ sec²

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Topics: Electrostatics (146)
Subject: Physics (2479)

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