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The acceleration due to gravity near the surface of a planet of radius R and density d is proportional to
Options
(a) d/R²
(b) dR²
(c) dR
(d) d/R
Correct Answer:
dR
Explanation:
g=GM/R²
(M=Mass of the earth); (R=Distance of body from centre of earth)
g=G Volume x density / R²
Volume of the sphere=4/3 πR³
Therefore, g=G.4/3 πR³.d / R²
g=G 4/3 πRd
g=4πG/3.dR
g is proportional to dR
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Perfectly black body radiates the energy 18 J/s at 300K. Another ordinary body of e=0.8
- The molecular weight of a gas is 44. The volume occupied by 2.2 g of this gas
- The frequencies of X-rays,γ-rays and ultraviolet rays are respectively p,q and r
- The ratio of the radii or gyration of a circular disc to that of a circular ring
- A particle under the action of a constant force moves from rest upto 20 seconds
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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