| ⇦ | 
| ⇨ |
The acceleration due to gravity at a place is π² m/sec². Then the time period of a simple pendulum of length one metre is
Options
(a) 2/π sec
(b) 2π sec
(c) 2 sec
(d) π sec
Correct Answer:
2 sec
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The equations of motion of a projectile are given by x=36 t metre and 2y=96t-9.8t²
- Monochromatic radiation emitted when electron on hydrogen atom
- A particle moving along X-axis has acceleration f,at time t given by f=fₒ(1- t/T)
- The energy band gap is maximum in
- A long wire carrying a steady current is bent into a circular loop of one turn.
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The equations of motion of a projectile are given by x=36 t metre and 2y=96t-9.8t²
- Monochromatic radiation emitted when electron on hydrogen atom
- A particle moving along X-axis has acceleration f,at time t given by f=fₒ(1- t/T)
- The energy band gap is maximum in
- A long wire carrying a steady current is bent into a circular loop of one turn.
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply