| ⇦ |
| ⇨ |
The acceleration due to gravity at a place is π² m/sec². Then the time period of a simple pendulum of length one metre is
Options
(a) 2/π sec
(b) 2π sec
(c) 2 sec
(d) π sec
Correct Answer:
2 sec
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Water rises to a height h in capillary tube. If the length of capillary tube above
- Two 220V – 100W bulbs are connected first in series and then in parallel.
- A nuclear reaction is given as 4 ₁H¹→₂He⁴+₀e¹+energy Mention the type of reaction.
- Two rigid bodies A and B rotate with rotational kinetic energies Eᴀ and Eʙ
- The power factor of an AC circuit having resistance R and inductance L connected
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Water rises to a height h in capillary tube. If the length of capillary tube above
- Two 220V – 100W bulbs are connected first in series and then in parallel.
- A nuclear reaction is given as 4 ₁H¹→₂He⁴+₀e¹+energy Mention the type of reaction.
- Two rigid bodies A and B rotate with rotational kinetic energies Eᴀ and Eʙ
- The power factor of an AC circuit having resistance R and inductance L connected
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply