| ⇦ |
| ⇨ |
Specific conductance of 0.1 M nitric acid is 6.3 ˣ 10⁻² ohm⁻¹ cm⁻¹.The molar conductance of solution is
Options
(a) 630 ohm⁻¹ cm² mol⁻¹
(b) 315 ohm⁻¹ cm² mol⁻¹
(c) 100 ohm⁻¹ cm² mol⁻¹
(d) 6,300 ohm⁻¹ cm² mol⁻¹
Correct Answer:
630 ohm⁻¹ cm² mol⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The rate of reactions exhibiting negative activation energy
- Sea weeds are an important source of
- If 10 cm³ solution of H₂O₂ ,on decomposition gives 150 cm³ of O₂
- Which of the following polymers is hard
- The equivalent weight of phosphoric acid(H₃PO₄) in the reaction
Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The rate of reactions exhibiting negative activation energy
- Sea weeds are an important source of
- If 10 cm³ solution of H₂O₂ ,on decomposition gives 150 cm³ of O₂
- Which of the following polymers is hard
- The equivalent weight of phosphoric acid(H₃PO₄) in the reaction
Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

630 option A.
Because ∆m=conductivity x 1000 divided by moralirty.