⇦ | ⇨ |
Specific conductance of 0.1 M nitric acid is 6.3 ˣ 10⁻² ohm⁻¹ cm⁻¹.The molar conductance of solution is
Options
(a) 630 ohm⁻¹ cm² mol⁻¹
(b) 315 ohm⁻¹ cm² mol⁻¹
(c) 100 ohm⁻¹ cm² mol⁻¹
(d) 6,300 ohm⁻¹ cm² mol⁻¹
Correct Answer:
630 ohm⁻¹ cm² mol⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - From the colligative properties of solution which one is the best method for
- Pauling’s electro negativity values for elements are useful in predicting
- which of the following compounds can be used as antifreeze in automobile radia
- Coordination number of Zn in ZnS (zinc blende) is
- A buffer solution contains 0.1 M of acetic acid and 0.1 M of sodium acetate.
Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- From the colligative properties of solution which one is the best method for
- Pauling’s electro negativity values for elements are useful in predicting
- which of the following compounds can be used as antifreeze in automobile radia
- Coordination number of Zn in ZnS (zinc blende) is
- A buffer solution contains 0.1 M of acetic acid and 0.1 M of sodium acetate.
Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
630 option A.
Because ∆m=conductivity x 1000 divided by moralirty.