| ⇦ | 
| ⇨ |
Solution of 0.1 N NH₄OH and 0.1 N NH₄Cl has pH 9.25 . Then fine out pKb of NH₄OH
Options
(a) 9.25
(b) 4.75
(c) 3.75
(d) 8.25
Correct Answer:
4.75
Explanation:
Solution of 0.1 N NH₄OH and 0.1 N NH₄Cl is a buffer solution.
According to Henderson equation,
The pH of a basic buffer,
pH = 14 -pK(b) – log{C(salt)/C(base)}.
⇒pK(b) = 14-pH-log{C(salt)/C(base)},
⇒ pK(b) = 14-9.25-log{0.1/0.1}.
⇒ pK(b) = 14-9.25 = 4.75.
Therefore pK(b) of NH₄OH = 4.75.
Related Questions: - A no. of ionic compounds, e.g., AgCl, CaF₂, BaSO₄ are insoluable in water
- Which of the following is electron-deficient?
- Which of the following on addition of water in presence of acid gives a ketone
- The crystal structure of NaCl is
- Which of the following elements are analogous to the lanthanides
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A no. of ionic compounds, e.g., AgCl, CaF₂, BaSO₄ are insoluable in water
- Which of the following is electron-deficient?
- Which of the following on addition of water in presence of acid gives a ketone
- The crystal structure of NaCl is
- Which of the following elements are analogous to the lanthanides
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply