| ⇦ |
| ⇨ |
For distinguishing phenol and acetic acid we required to react (treat) them with
Options
(a) Na₂CO₃
(b) NaOH
(c) HCl
(d) NaHCO₃
Correct Answer:
NaHCO₃
Explanation:
Acetic acid on treatment with NaHCO₃ evolves CO₂, however no such reaction occurs with phenol. CH₃COOH + NaHCO₃ → CH₃COONa + CO₂↑ + H₂O.
Related Questions: - Diffusion of solvent through a semi permeable membrane is called
- Acetaldehyde can not show
- The hybridisation of carbons of C-C single bond of HC ≡C-CH =CH₂ is
- Which of the following compounds is the strongest base
- One gram sample NH₄NO₃ is decomposed in a bomb calorimeter.
Topics: Alcohols Phenols and Ethers
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Diffusion of solvent through a semi permeable membrane is called
- Acetaldehyde can not show
- The hybridisation of carbons of C-C single bond of HC ≡C-CH =CH₂ is
- Which of the following compounds is the strongest base
- One gram sample NH₄NO₃ is decomposed in a bomb calorimeter.
Topics: Alcohols Phenols and Ethers (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply