| ⇦ | 
| ⇨ |
Solution of 0.1 N NH₄OH and 0.1 N NH₄Cl has pH 9.25 . Then fine out pKb of NH₄OH
Options
(a) 9.25
(b) 4.75
(c) 3.75
(d) 8.25
Correct Answer:
4.75
Explanation:
Solution of 0.1 N NH₄OH and 0.1 N NH₄Cl is a buffer solution.
According to Henderson equation,
The pH of a basic buffer,
pH = 14 -pK(b) – log{C(salt)/C(base)}.
⇒pK(b) = 14-pH-log{C(salt)/C(base)},
⇒ pK(b) = 14-9.25-log{0.1/0.1}.
⇒ pK(b) = 14-9.25 = 4.75.
Therefore pK(b) of NH₄OH = 4.75.
Related Questions: - Which one of the following statements concerning lanthanides elements is false
- In the periodic table from left to right in a period,the atomic volume
- Which of the following has tetrahedral
- In the Dumas method of estimation of nitrogen,the nitrogen in the organic compound
- which of the following oxy acids of phosphorus is a reducing agent and monobasic
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which one of the following statements concerning lanthanides elements is false
- In the periodic table from left to right in a period,the atomic volume
- Which of the following has tetrahedral
- In the Dumas method of estimation of nitrogen,the nitrogen in the organic compound
- which of the following oxy acids of phosphorus is a reducing agent and monobasic
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply