| ⇦ | 
| ⇨ |
Solution of 0.1 N NH₄OH and 0.1 N NH₄Cl has pH 9.25 . Then fine out pKb of NH₄OH
Options
(a) 9.25
(b) 4.75
(c) 3.75
(d) 8.25
Correct Answer:
4.75
Explanation:
Solution of 0.1 N NH₄OH and 0.1 N NH₄Cl is a buffer solution.
According to Henderson equation,
The pH of a basic buffer,
pH = 14 -pK(b) – log{C(salt)/C(base)}.
⇒pK(b) = 14-pH-log{C(salt)/C(base)},
⇒ pK(b) = 14-9.25-log{0.1/0.1}.
⇒ pK(b) = 14-9.25 = 4.75.
Therefore pK(b) of NH₄OH = 4.75.
Related Questions: - If Ksp for HgSO₄ is 6.4 x 10⁻⁵, then solubility of the salt is
- Which of the following is most volatile
- Diamond is used I glass cutting due to its
- In a face-centered cubic lattice, a unit cell is shared equally by how many unit
- If 0.2 gram of an organic compound containing carbon, hydrogen and oxygen
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If Ksp for HgSO₄ is 6.4 x 10⁻⁵, then solubility of the salt is
- Which of the following is most volatile
- Diamond is used I glass cutting due to its
- In a face-centered cubic lattice, a unit cell is shared equally by how many unit
- If 0.2 gram of an organic compound containing carbon, hydrogen and oxygen
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply