| ⇦ | 
| ⇨ |
Solution of 0.1 N NH₄OH and 0.1 N NH₄Cl has pH 9.25 . Then fine out pKb of NH₄OH
Options
(a) 9.25
(b) 4.75
(c) 3.75
(d) 8.25
Correct Answer:
4.75
Explanation:
Solution of 0.1 N NH₄OH and 0.1 N NH₄Cl is a buffer solution.
According to Henderson equation,
The pH of a basic buffer,
pH = 14 -pK(b) – log{C(salt)/C(base)}.
⇒pK(b) = 14-pH-log{C(salt)/C(base)},
⇒ pK(b) = 14-9.25-log{0.1/0.1}.
⇒ pK(b) = 14-9.25 = 4.75.
Therefore pK(b) of NH₄OH = 4.75.
Related Questions: - Colloidal found effective in medicines is
- Which is the redox reaction
- The number of moles of KMnO₄ that will be needed to react with one mole of
- Oxidation state of Fe in Mohr’s salt is
- Which of the following elements will have the highest electron affinity
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Colloidal found effective in medicines is
- Which is the redox reaction
- The number of moles of KMnO₄ that will be needed to react with one mole of
- Oxidation state of Fe in Mohr’s salt is
- Which of the following elements will have the highest electron affinity
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply