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Ratio of Cᵥ and Cᵥ of the gas X is 1.4. The number of atoms of the gas X present in 11.2 litres of it at NTP will be
Options
(a) 6.02 x 10²³
(b) 1.2 x 10²³
(c) 3.01 x 10²³
(d) 2.01 x 10²³
Correct Answer:
6.02 x 10²³
Explanation:
gas is diatomic based on Cₚ and Cᵥ ratio
According to Avogadro’s hypothesis we have come to know that the molar volume of a gas at STP is 22.4 litres
22.4 litre at NTP = 6.02 x 10²³ molecules
11.2 L at NTP = 3.01 x 10²³ molecules
= 3.01 x 10²³ molecules x 2 atoms = 6.02 x 10²³ molecules
Related Questions: - The boiling point of glycerol is more than propanol because of
- This radical can be identified by Borax bead test is
- In the photo-electron emission,the energy of the emitted electron is
- The number of gram molecules of oxygen in 6.02 x 10²⁴ CO molecules is
- In which of the following compounds manganese has oxidation number equal
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The boiling point of glycerol is more than propanol because of
- This radical can be identified by Borax bead test is
- In the photo-electron emission,the energy of the emitted electron is
- The number of gram molecules of oxygen in 6.02 x 10²⁴ CO molecules is
- In which of the following compounds manganese has oxidation number equal
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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