Ratio of Cᵥ and Cᵥ of the gas X is 1.4. The number of atoms of the gas X present

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Ratio of Cᵥ and Cᵥ of the gas X is 1.4. The number of atoms of the gas X present in 11.2 litres of it at NTP will be

Options

(a) 6.02 x 10²³
(b) 1.2 x 10²³
(c) 3.01 x 10²³
(d) 2.01 x 10²³

Correct Answer:

6.02 x 10²³

Explanation:

gas is diatomic based on Cₚ and Cᵥ ratio
According to Avogadro’s hypothesis we have come to know that the molar volume of a gas at STP is 22.4 litres
22.4 litre at NTP = 6.02 x 10²³ molecules
11.2 L at NTP = 3.01 x 10²³ molecules
= 3.01 x 10²³ molecules x 2 atoms = 6.02 x 10²³ molecules

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Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)

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