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Ratio of Cᵥ and Cᵥ of the gas X is 1.4. The number of atoms of the gas X present in 11.2 litres of it at NTP will be
Options
(a) 6.02 x 10²³
(b) 1.2 x 10²³
(c) 3.01 x 10²³
(d) 2.01 x 10²³
Correct Answer:
6.02 x 10²³
Explanation:
gas is diatomic based on Cₚ and Cᵥ ratio
According to Avogadro’s hypothesis we have come to know that the molar volume of a gas at STP is 22.4 litres
22.4 litre at NTP = 6.02 x 10²³ molecules
11.2 L at NTP = 3.01 x 10²³ molecules
= 3.01 x 10²³ molecules x 2 atoms = 6.02 x 10²³ molecules
Related Questions: - Heat of combustion ΔH for C(s) , H₂(g)and CH₄(g) are -94, -68 and -213 kcal/mol.
- The oxidising ability of halogens
- Chloroform gives a trichloro derivative of an alcohol on reaction with
- Ethylene glycol reacts with excess of PCl₅ to give
- The strength of H₂O₂ (in g/litre) in 11.2 volume solution of H₂O₂ is
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Heat of combustion ΔH for C(s) , H₂(g)and CH₄(g) are -94, -68 and -213 kcal/mol.
- The oxidising ability of halogens
- Chloroform gives a trichloro derivative of an alcohol on reaction with
- Ethylene glycol reacts with excess of PCl₅ to give
- The strength of H₂O₂ (in g/litre) in 11.2 volume solution of H₂O₂ is
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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