| ⇦ | 
| ⇨ |
Radius of a soap bubble is increased from R to 2R. Work done in this process in terms of surface tension S is
Options
(a) 24 πR²S
(b) 48 πR²S
(c) 12 πR²S
(d) 36 πR²S
Correct Answer:
24 πR²S
Explanation:
Work done = 2 x S x Change in surface area
W = 2 x S x 4π (R₂² – R₁²)
Given: R₂ = 2R, R₁ = R = 8S π (4R² – R²) = 24 πR²S.
Related Questions: - The average power dissipated in a pure inductor is
- A long straight wire is carrying a current of 12 A. The magnetic field at a distance
- If the feedback voltage is increased in a negative feedback amplifier, then
- In a diffraction pattern due to a singleslit of width a, the first minimum is observed
- The force F acting on a particle of mass m is indicated by the force-time graph
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The average power dissipated in a pure inductor is
- A long straight wire is carrying a current of 12 A. The magnetic field at a distance
- If the feedback voltage is increased in a negative feedback amplifier, then
- In a diffraction pattern due to a singleslit of width a, the first minimum is observed
- The force F acting on a particle of mass m is indicated by the force-time graph
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply