| ⇦ | 
| ⇨ |
Periodic time of a satellite revolving above Earth’s surface at a height equal to R, radius of Earth is (g=acceleration due to gravity at Earth’s surface)
Options
(a) 2π√2R/g
(b) 4√2√R/g
(c) 2π√R/g
(d) 8π√R/g
Correct Answer:
4√2√R/g
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Complete the reaction: ₀n¹+ ₉₂U²³⁵→₅₆Ba¹⁴⁴+……..+3n
- On a frictionless surface, a block of mass M moving at speed v collides elastically
- The frequency of light ray having the wavelength 3000Å is
- A carbon film resistor has colour code green, black, violet, gold. The value
- A simple pendulum is suspended from the ceiling of a lift. When the lift is at rest
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Complete the reaction: ₀n¹+ ₉₂U²³⁵→₅₆Ba¹⁴⁴+……..+3n
- On a frictionless surface, a block of mass M moving at speed v collides elastically
- The frequency of light ray having the wavelength 3000Å is
- A carbon film resistor has colour code green, black, violet, gold. The value
- A simple pendulum is suspended from the ceiling of a lift. When the lift is at rest
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply