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Periodic time of a satellite revolving above Earth’s surface at a height equal to R, radius of Earth is (g=acceleration due to gravity at Earth’s surface)
Options
(a) 2π√2R/g
(b) 4√2√R/g
(c) 2π√R/g
(d) 8π√R/g
Correct Answer:
4√2√R/g
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two solid discs of radii r and 2r roll from the top of an inclined plane
- What are the unit of K = 1 / (4 π ?￢ﾂﾒ)
- A particle of masses m is thrown upwards from the surface of the earth, with a velocity u
- The ionisation energy of hydrogen is 13.6 eV. The energy of the photon released
- A DC ammeter has resistance 0.1Ω and its current ranges 0-100A. If the range
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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