| ⇦ | 
| ⇨ |
Periodic time of a satellite revolving above Earth’s surface at a height equal to R, radius of Earth is (g=acceleration due to gravity at Earth’s surface)
Options
(a) 2π√2R/g
(b) 4√2√R/g
(c) 2π√R/g
(d) 8π√R/g
Correct Answer:
4√2√R/g
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A radioactive nucleus of mass M emits a photon of frequency v and the nucleus recoils.
- A generator at a utility company produces 100 A of current at 4000 V. The voltage
- An electron moving in a circular orbit of radius r makes n rotations per second.
- A motorcycle moving with a velocity 72 kmh⁻¹ on a flat road takes a turn
- A vertical spring with force constant k is fixed on a table. A ball of mass
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A radioactive nucleus of mass M emits a photon of frequency v and the nucleus recoils.
- A generator at a utility company produces 100 A of current at 4000 V. The voltage
- An electron moving in a circular orbit of radius r makes n rotations per second.
- A motorcycle moving with a velocity 72 kmh⁻¹ on a flat road takes a turn
- A vertical spring with force constant k is fixed on a table. A ball of mass
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply