| ⇦ |
| ⇨ |
Oxidation number of chromium in Na₂Cr₂O₇ is
Options
(a) 2
(b) 4
(c) 3
(d) 6
Correct Answer:
6
Explanation:
Oxidation number of chromium in Na₂Cr₂O₇ is +6. Oxidation number of Na = +1. Oxidation number of O = -2. Therefore 2 + 2x -2 * 7 = 0.⇒ 2x – 12 = 0 , ⇒ x = +6.
Related Questions: - When 22.4 litres of H₂(g) is mixed with 11.2 litres of Cl₂(g) each at S.T.P,
- The bond angle in water is
- The law of equilibrium was first given by
- When CO₂ is passed through solution of calcium hydroxide,Which one of the
- How many g of silver will be displaced from a solution of AgNO₃ by 4 g of mag
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When 22.4 litres of H₂(g) is mixed with 11.2 litres of Cl₂(g) each at S.T.P,
- The bond angle in water is
- The law of equilibrium was first given by
- When CO₂ is passed through solution of calcium hydroxide,Which one of the
- How many g of silver will be displaced from a solution of AgNO₃ by 4 g of mag
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply