| ⇦ | 
| ⇨ |
On bombarding U²³⁵ by slow neutron, 200 MeV energy is released. If the power output of atomic reactor is 1.6 MW, then the rate of fission will be
Options
(a) 8×10¹⁶/s
(b) 20×10¹⁶/s
(c) 5×10²²/s
(d) 5×10¹⁶/s
Correct Answer:
5×10¹⁶/s
Explanation:
Energy released per fission of uranium = 200 × 10⁶ × 1 × 10⁻¹⁹ J
Power output = 1.6 × 10⁶ W
Number of fission /s = 1.6 × 10⁶ / 200 × 10⁶ × 1 × 10⁻¹⁹ = 5 × 10¹⁶ /s
This is the rate of fission.
Related Questions: - The original temperature of a black body is 727⁰C. The temperature at which this black
- A particle moves a distance x in time but according to equation x=(t+5)⁻¹
- In a given process on an ideal gas, dW=0 and dQ<0. Then for the gas
- A nucleus ᵐₙ X emits one α- particle and two β- particles. The resulting nucleus is
- Two spherical nuclei have mass numbers 216 and 64 with their radii R₁ and R₂,
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The original temperature of a black body is 727⁰C. The temperature at which this black
- A particle moves a distance x in time but according to equation x=(t+5)⁻¹
- In a given process on an ideal gas, dW=0 and dQ<0. Then for the gas
- A nucleus ᵐₙ X emits one α- particle and two β- particles. The resulting nucleus is
- Two spherical nuclei have mass numbers 216 and 64 with their radii R₁ and R₂,
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply