| ⇦ | 
| ⇨ |
On bombarding U²³⁵ by slow neutron, 200 MeV energy is released. If the power output of atomic reactor is 1.6 MW, then the rate of fission will be
Options
(a) 8×10¹⁶/s
(b) 20×10¹⁶/s
(c) 5×10²²/s
(d) 5×10¹⁶/s
Correct Answer:
5×10¹⁶/s
Explanation:
Energy released per fission of uranium = 200 × 10⁶ × 1 × 10⁻¹⁹ J
Power output = 1.6 × 10⁶ W
Number of fission /s = 1.6 × 10⁶ / 200 × 10⁶ × 1 × 10⁻¹⁹ = 5 × 10¹⁶ /s
This is the rate of fission.
Related Questions: - The coefficient of performance of a refrigerator is 5. If the temperature inside
- Two particles of masses m₁ m₂ move with initial velocities u₁ and u₂
- The ferromagnetic substance is
- At what distance from the centre of earth, the value of acceleration due to gravity
- A particle is dropped from a building. It takes 4 sec for the particle to reach the ground
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The coefficient of performance of a refrigerator is 5. If the temperature inside
- Two particles of masses m₁ m₂ move with initial velocities u₁ and u₂
- The ferromagnetic substance is
- At what distance from the centre of earth, the value of acceleration due to gravity
- A particle is dropped from a building. It takes 4 sec for the particle to reach the ground
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply